Acessing The Return Array

Question

edit:

<?php
    $file= 'fbplus.jpg';

    $args = array(
       'message' => $album_message,
    );
    $args[basename($file)] = '@' . realpath($file);
    $ch = curl_init();
    $url = $graph_url;
    curl_setopt($ch, CURLOPT_URL, $url);
    curl_setopt($ch, CURLOPT_HEADER, false);
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
    curl_setopt($ch, CURLOPT_POST, true);
    curl_setopt($ch, CURLOPT_POSTFIELDS, $args);
    $data = curl_exec($ch);
    //returns the photo id
    print_r(json_decode($data,true));


    echo "$data['id'] "; //wont work
        echo "$data[id] "; //wont work


?>

this was the return, after i successfully uploaded a photo.

Array ( [id] => 112235735579158 [post_id] => 100003781972892_112203478915717 )

Isn't that an assoc. array? Should be `$data['id']` instead of `$data[id]` — Smamatti, Apr 28 '12 at 10:48
If that is the array, then $data['id'] should work. Also, please use long open tags. Later down the road when you're stuck on a server that doesn't have short open tags enabled, you'll likely regret it. — Corbin, Apr 28 '12 at 10:49
@Smamatti, yes, syntactically, `id` should be in quotes, but that's not what's causing the problem here. — Nadh, Apr 28 '12 at 10:49
@NADH Alright, thanks! Wasn't sure about the return value, because it stated `mixed` in the API. Guess you are right then in your answer :-) — Smamatti, Apr 28 '12 at 10:55
@NADH because he want to put it somewhere i html that why he use but is the same as or = json_encode($data)['id'] ?> but don't think that php allow to use index after a function call. Didn't read question carefully. — jcubic, Apr 28 '12 at 10:55
@jcubic, `short_open_tag` (` ?>`) is deprecated, and was removed in PHP 5.3.0 — Nadh, Apr 28 '12 at 10:58
@NADH: I think (might be wrong) that jcubic meant that `=` is also a short open tag and should also not be used: http://stackoverflow.com/questions/200640/are-php-short-tags-acceptable-to-use — Stefan, Apr 28 '12 at 10:59
@jcubic, `= ?>` is valid usage. However, it's only available in PHP 5.4.0+ and in versions before 5.3.0. — Nadh, Apr 28 '12 at 11:03
@jcubic: It's only 'valid' if the server has short tags enabled. — Stefan, Apr 28 '12 at 11:06
i edited the code. still cant access it. i just had problem posting thats why. its my first post — Roxy Gutera, Apr 28 '12 at 11:09

Nadh · Accepted Answer · 2012-04-28T11:09:50.830

2

curl_exec() returns a string (contents of the webpage), not an Array. So you cannot do $data['id'] because $data is a string and not an array.

What is the url you are posting to? What is its exact output?

EDIT: Looks like the url returns JSON. In that case:

<?php
    $file= 'fbplus.jpg';

    $args = array(
       'message' => $album_message,
    );
    $args[basename($file)] = '@' . realpath($file);
    $ch = curl_init();
    $url = $graph_url;
    curl_setopt($ch, CURLOPT_URL, $url);
    curl_setopt($ch, CURLOPT_HEADER, false);
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
    curl_setopt($ch, CURLOPT_POST, true);
    curl_setopt($ch, CURLOPT_POSTFIELDS, $args);
    $data = curl_exec($ch);
    //returns the photo id

    $data = json_decode($data,true);

    echo $data['id'];
?>

edited Apr 28 '12 at 11:09

answered Apr 28 '12 at 10:48

Nadh

6,987
2
21
21

i used this print_r(json_decode($data,true)); the output is Array ( [id] => 112265748909490 [post_id] => 100003781972892_112203478915717 ) . then why is it an array? – Roxy Gutera Apr 28 '12 at 10:58
Ah, it's an array because you are using `json_decode()` which you did not mention in your original question. – Nadh Apr 28 '12 at 11:04
@RoxyGutera, I've edited my answer with code that works. While you are doing a `json_decode()` inside `print_r()`, you are not assigning it to the `$data` variable! – Nadh Apr 28 '12 at 11:10
the output is { (one curly brace) . whats happening? – Roxy Gutera Apr 28 '12 at 11:15
sorry about that i forgot to remove the print_r. thanks NADH it worked – Roxy Gutera Apr 28 '12 at 11:17

score 0 · Answer 2 · answered Apr 28 '12 at 10:49

0

Are you accessing the Facebook Graph API?

If so just use:

$data = json_decode($data);

and the you can access it trough $data->id

answered Apr 28 '12 at 10:49

Diogo Raminhos

2,023
16
24

that was my first approach but still $data->id is NULL. yes graph api and $data = json_decode($data); is in my code already. but still i cant access the array – Roxy Gutera Apr 28 '12 at 10:54
@Roxy, by default, `json_decode()` returns an object. If you want to get an array, try `json_decode($data, true)` – Nadh Apr 28 '12 at 10:59

Acessing The Return Array

2 Answers2