Is it possible to not generate service part of wsdl contract in WCF?

Question

I've written a WCF service and wonder if it somehow possible to not get the service part:

<wsdl:service name="MyService">
<wsdl:port name="BasicHttpBinding_MyService" binding="tns:BasicHttpBinding_MyService">
  <soap:address location="http://localhost:8000/MyService/Service" />
</wsdl:port>

generetad either directly in the wsdl or when svcutil pulls it down.

Or maybe it's easier to write a powershell script that just removes the service element?

score 2 · Answer 1 · answered Apr 24 '12 at 18:04

2

implement IWsdlExportExtension. Inside it remove the parts you do not want:

http://msdn.microsoft.com/en-us/library/system.servicemodel.description.iwsdlexportextension.aspx

answered Apr 24 '12 at 18:04

Yaron Naveh

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score 0 · Accepted Answer · answered Apr 24 '12 at 16:20

0

It is not possible to prevent the built-in metadata from emitting the service portion of the WSDL.

Your options are to create a new metadata behavior, or even simpler, to turn off the metadata and simply provide a handcrafted WSDL via a well known Url.

answered Apr 24 '12 at 16:20

Ethan Cabiac

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20
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Thanks, I thought as much, but you never know if there's some weird setting to use. :) – Markus Apr 25 '12 at 11:01

Is it possible to not generate service part of wsdl contract in WCF?

2 Answers2