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I recently wrote a program after analyzing the k-th smallest element algorithm, first without the case of duplicates.

Now, however, I would like to analyze the expected asymptotic runtime for finding, say, the median of an array when there are exactly j duplicates. I haven't modified my code for such, and thus the performance slows down a bit because of the j duplicates.

I'm not sure how to begin? Can anyone point me towards such a recurrence relation?

I've derived the following, where n is the size of the input array

T(n) <= 1/2*T(3/4*n) + 1/2*T(n)

but am quite unclear how to proceed with duplicate keys involved.

Thanks

UmNyobe
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CyberShot
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1 Answers1

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The randomized solution as demonstrated here is 

 T(n) <= T(3/4*n) + n-1  =>  T(n) <= 4n

The complexity of the algorithm may depend on j but don't expect it to be miraculously less than linear time. Why? take a random array of size n/2, duplicate it completely and run the ideal algorithm for the problem with duplicates. You'll have

T(n) <= 4(n/2) => T(n) <= 2n

when each element is duplicated twice (exactly n/2 duplicates)

UmNyobe
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