Escaped Quotes in PHP for Sed Command

Question

I have the following php code

if (!($stream = ssh2_exec($con, 'sed -i \'s/motd=A Minecraft Server/motd=\'.$name.\'s     Server/g\' /home/servers/runner15/server.properties
'))) {

But when I run it instead of replacing the text "motd=A Minecraft Server" to "motd=runner15s Server" it Changes it to motd=..s Server

It's something todo with escaping the quotes

Oh by the way $name holds runner15

Marc B · Accepted Answer · 2012-04-22T21:36:22.733

2

Basic PHP strings... ' strings do NOT interpolate variables, so your sed command contains a literal $, n, a, m, e, etc... That'll be interpreted as a non-existent shell varaible on the remote server, and expand to an empty string.

[...snip...]otd=A Minecraft Server/motd=\''.$name.'\'s [..snip...]
                                          ^-------^--- 'exit' the string in your client-side PHP

edited Apr 22 '12 at 21:36

answered Apr 22 '12 at 21:24

Marc B

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I'm a little confused on the vocabulary used, can you try to explain it to me a little more please? Thank you so much for your help! – Jeremy Sayers Apr 22 '12 at 21:27
`$name` is not substituted in `'$name'` (single quotes!) – Karoly Horvath Apr 22 '12 at 21:33

score 0 · Answer 2 · answered Apr 22 '12 at 21:31

0

Try escapeshellcmd before ssh2_exec. http://www.php.net/manual/en/function.escapeshellcmd.php

answered Apr 22 '12 at 21:31

alganet

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Escaped Quotes in PHP for Sed Command

2 Answers2