I want to get strings that have specific length in NSArray.
The array has many elements and I don't want to use fast enumeration.
Is there a possible way?
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No matter how you do it you'll get the same function "under the covers" -- iterate through the array and test the individual strings for their length. Using something like filteredArrayWithPredicate might save a few cycles vs doing it in the straight-forward fashion, or might be slower, hard to predict. – Hot Licks Apr 18 '12 at 11:32
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(Of course you could always keep separately some sort of list of string lengths, and search that. But then there's the overhead of preparing the list.) – Hot Licks Apr 18 '12 at 11:34
3 Answers
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No matter what you do you will be using fast enumeration whether you realize it or not. However, have you considered using an NSPredicate object and the filteredArrayWithPredicate method?
borrrden
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This works like a charm:
NSPredicate *predicate = [NSPredicate predicateWithFormat:@"self.length == %d", lenght];
NSArray *filtered = [array filteredArrayUsingPredicate:predicate];
Christian Schnorr
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NSArray *yourArray = [[NSArray alloc] initWithObjects:@"Apple, Orange, Grapes, Cherry, nil"];
for(NSString *element in yourArray){
if(element.length==yourLength){
[filteredArray addObject:element];
}
}
NSLog(@"Filtered array now contains the elements with length %d", yourLength);
NSLog(@"Filtered array--%@", filteredArray);
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See @borrrden's answer, even my answer (which you accepted) uses fast enumeration under the hood. – Christian Schnorr Apr 18 '12 at 12:08