I have created a service data access layer where there are multiple databases where data needs to come from.
I was doing fine with one database where I defined the memberRepository
that contained member details. However, now I have to get session-related details that are stored in another database.
OprationContracts:
IMemberServices
containsGetLoggedInBuddies(int profileID);
ISessionServices
containsGetProfileIDFromSessionID(string sessionID);
My service class:
public class MemberService : IMemberService, ISessionServices
{
#region Strategy pattern configuration
//
// Member repo
//
private MemberRepository memberRepository;
public MemberService()
: this(new MemberRepository())
{ }
public MemberService(MemberRepository memberRepository)
{
this.memberRepository = memberRepository;
}
//
// Session repo
//
private SessionRepository sessionRepository;
public MemberService() : this(new SessionRepository()){}
public MemberService(SessionRepository sessionRepository)
{
this.sessionRepository = sessionRepository;
}
#endregion
/// <summary>
/// Session-related details are maintained in the Secondary database
/// </summary>
/// <param name="sessionID"></param>
/// <returns></returns>
public int GetProfileIDFromSessionID(string sessionID)
{
int sessionProfileID = sessionRepository.GetProfileDetailsFromSessionID(sessionRepository);
return sessionProfileID;
}
/// <summary>
/// Try profileID = 1150526
/// </summary>
/// <param name="profileID"></param>
public void GetLoggedInBuddies(int profileID)
{
memberRepository.GetLoggedInBuddies(profileID);
//return memberRepository.GetLoggedInBuddies(profileID);
}
The issue is that in the // Session Repo
section, as I already have a constructor defined. I get that.
So basically in each method I want to do something like
MemberService useSessionRepo = new MemberService(SessionRepository);
useSessionRepo.GetProfileDetailsFromSessionID(...);
MemberService useMemberRepo = new MemberService(MemberRepository);
useMemberRepo.GetLoggedInBuddies(...);
Just need a hand putting this together.
Thanks.