How do I make a C program executable on the command line in Minix 3?

Question

I need to make a program, ioloop.c, which takes two command line parameters that determine the number of iterations of two nested for loops. The inner loop performs a more time-consuming function, such as a trig function. The outer loop first takes a character from stdin, then outputs some number of characters after the inner loop.

My issue has been finding adequate resources on the internet about Minix 3. I haven't found any good tutorials yet that explain the process of implementing a command line method. My first assumption would be that it has something to do with the exec system call.

Any help or explanation on which Minix 3 files are used to implement command line functions would be awesome.

Marek Bardoński · Accepted Answer · 2012-04-09T06:04:35.563

1

You can use arguments in main function of program

(...)
int main(int artc, char argv[3]){
 int n1 = atoi(argv[1]);
 int n2 = atoi(argv[2]);
(...)

Where n1 and n2 are command line parameters. Then if You call

./a.out 100 2000

n1 will be set to 100 and n2 will be 2000

edited Apr 09 '12 at 06:04

answered Apr 08 '12 at 22:04

Marek Bardoński

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I tried it, and on the line "int main(int artc, char[] argv)" I got an error: "expected ';' , ',' or ')' before 'argv' when I tried to compile. – Garrison_Laforge Apr 09 '12 at 04:35
That didn't work either, lol, but I figured it out. The correct syntax was: int main(int artc, char **argv) – Garrison_Laforge Apr 10 '12 at 13:33

How do I make a C program executable on the command line in Minix 3?

1 Answers1