How can i make a Method that rounds to the next 5er digit?

Question

Possible Duplicate:
Built in .Net algorithm to round value up to the nearest 10 interval

HI, i need a Method that returns next number of the 5er row. example: 3 -> 5 7 -> 10 8 -> 10 16 ->20

how can i do that? thx

I voted to close "exact duplicate". http://stackoverflow.com/questions/274439/built-in-net-algorithm-to-round-value-up-to-the-nearest-10-interval — Andrew Hare, Jun 17 '09 at 11:50
Not an exact duplicate -- he wants to always round up, not to the nearest. — tvanfosson, Jun 17 '09 at 11:52

score 2 · Accepted Answer · answered Jun 17 '09 at 11:51

2

For positive values:

int rounded  = 5 * Math.Ceiling( (double)original / 5 );

answered Jun 17 '09 at 11:51

tvanfosson

b.roth · Answer 2 · 2009-06-17T12:10:33.610

0

   int rounded = original + (5 - original%5);

edited Jun 17 '09 at 12:10

answered Jun 17 '09 at 12:03

b.roth

That's 4/5 good, but for 0 you get 5, 5->10, 10->15, etc. 10%5 is zero, last time I've checked. – Kobi Jun 17 '09 at 12:26
Kobi, you're right. I should have written this as: rounded = n%5==0?n:n + (5 - n%5) – b.roth Jun 17 '09 at 12:36
FYI, neither of your versions works correctly for negative numbers. – Eric Lippert Jun 17 '09 at 15:20

2 Answers2