python 2.7: Getting Segmentation fault when setting Menu in GUI programming with Tkinter

Question

I'm getting a segmentation fault everytime i want to run this code :

from Tkinter import *
def gui():  
        root=Tk()
        menubar=Menu(root)
        filemenu=Menu(menubar,tearoff=0)
        filemenu.add_command(label='New',command=gui)
        filemenu.add_command(label='Close',command=root.quit)
        menubar.add_cascade(label='File',menu=filemenu)
        helpmenu=Menu(menubar,tearoff=1)
        helpmenu.add_separator()
        helpmenu.add_command(label="Help")#ajouter commande
        helpmenu.add_command(label='About...')#ajouter commande
        helpmenu.add_cascade(label='Help',menu=helpmenu)
        root.mainloop()

gui()

Any suggestion ? What should i do ? Thank you in advance. MFF

In which OS you are running. I just ran your example code it went just fine. — Abhijit, Apr 07 '12 at 16:29
I just ran it in python 2.7.2 on mac osx Lion and got a seg fault as well. So probably OS X. — Nolen Royalty, Apr 07 '12 at 16:39
Works fine on Ubuntu 11.10, with Python 2.7.2. How long does it take for the segfault to come up? What OS are you using? — Makoto, Apr 07 '12 at 16:43

Nolen Royalty · Accepted Answer · 2012-04-07T16:50:11.930

5

The segfault is caused by:

helpmenu.add_cascade(label='Help',menu=helpmenu)

after a quick look at the docs, it makes perfect sense why that would give you problems. Add cascade "adds a hierarchical menu item". You are adding helpmenu as a menu within helpmenu.

I believe that what you mean here is

menubar.add_cascade(label="Help", menu=helpmenu)

edited Apr 07 '12 at 16:50

answered Apr 07 '12 at 16:45

Nolen Royalty

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Wow, Thank you ! ;) I was facing this for a while ! – Malik Fassi Apr 07 '12 at 16:55

python 2.7: Getting Segmentation fault when setting Menu in GUI programming with Tkinter

1 Answers1