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I am using xstream and trying to serialize a List to XML. I need an output structure like

<Employees>
  <Employee></Employee>
  <Employee></Employee>
  <Employee></Employee>
</Employees>

The object to serialize would be something like an 

 List<Employee>

or a class Employees. I've tried to create an Employees as 

public class Employees extends ArrayList<Employee>(){}

and various other approaches but can't get it to serialize as I need it. Is there an easy way to do such a thing?

My question is similar to XStream - Root as a collection of objects but I'd like to do it without a wrapper object.

Community
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James Morales
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1 Answers1

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You're using a list as your root element? You can alias the class. The code below produces the output you're looking for.

public static void main(String[] args) {
    List<Employee> employees = new ArrayList<Employee>();
    employees.add(new Employee());
    employees.add(new Employee());
    employees.add(new Employee());
    XStream xstream = new XStream();
    xstream.alias("Employees", List.class);
    System.out.println(xstream.toXML(employees));
}
Aaron Webb
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  • Maybe I don't understand how to use it correctly but what would the field name be if Users extends ArrayList? xstream.addImplicitCollection(Users.class, "??") – James Morales Apr 07 '12 at 04:12
  • xstream.alias("Employees", Users.class); I believe you'd need a custom converter at that point. http://xstream.codehaus.org/converter-tutorial.html – Aaron Webb Apr 08 '12 at 15:32