How do I grep last match in a range of files?

Question

I have files named memOutput.X where X ranges from 0 to 47 in a directory. I want to see the line with the last occurrence of VmData in all these files. I can run

grep VmData memOutput.0 | tail -1

to get the last match from one file but not sure how to do it for a range of files. Also, grep VmData memOutput.* | tail -1 displayed only the last match from file memOutput.47. Is there an alternative to grep?

Thanks.

Sirch · Accepted Answer · 2019-05-03T15:54:25.640

1

Use a loop?

for file in memOutput.*; do
    grep -H VmData "${file}" | tail -n 1
done

Or if you want a one-liner:

for file in memOutput.*; do grep -H VmData "${file}" | tail -n 1;done

edited May 03 '19 at 15:54

answered May 03 '19 at 15:24

Sirch

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It will work, but is there a one-liner way to do it? – nac001 May 03 '19 at 15:40
for file in memOutput.*; do grep -H VmData "${file}" | tail -n 1;done – Sirch May 03 '19 at 15:53

How do I grep last match in a range of files?

1 Answers1