Hello I am new to linux and grep and awk commands.
I am trying to get the number value from this string variable and then store it in another variable.
var1="Version must be incremented on update. Current version is: 532"
var2=var1 | grep "?"
What should I do in order to only retrieve val 532 from the above string and store it in var2
You need $var1 to reference it, rather than var1. You need to echo it so that Bash won't try to run it as a program. You should put double-quotes around it as well.
For grep, you need a regular expression to match the numbers, lots of patterns might work but I'm using "one or more digits, at the end of the string", and you need the grep option -o to print only the matching text, instead of the whole line.
Run this inside $() to stop the shell trying to run the result as a program, and your code looks like this:
var1="Version must be incremented on update. Current version is: 532"
var2=$(echo "$var1" | grep '[0-9]\+$' -o)
echo "$var2"
# 532
