linux sh -c replace echo not working

Asked May 11 '18 at 18:20

Active May 11 '18 at 18:36

Viewed 657 times

This seems like it should have a super simple answer, but I have search for a while and tried different suggestions to no avail.

As an example, I am trying to create a function that will be available when the following is ran

sh -c "echo 'test \c'"

I have tried adding the following code right after the shebang / first command in both /etc/profile and /etc/bashrc

echo () {
    builtin echo -e "$@"
}

What is frustrating is that it works in normal sh and bash when logged in. However as soon as sh -c is ran, it just forgets that ever existed. I have tried other tests, like making a function called echo2 and it doesn't exist in sh -c

Now here is the very frustrating thing, it HAS to be sh -c because the proprietary enterprise software application runs its commands inside of sh -c, which I cannot control that... So it HAS to be something that works natively with sh -c "something"

edited May 11 '18 at 18:36

asked May 11 '18 at 18:20

syntencoist

You'd need to export the function `export -f echo` but `sh` won't pick it up -- function exports are not POSIX. You'll need to implement it as a script. – glenn jackman May 11 '18 at 18:37
Is `sh` a link to bash? On ubuntu it is dash. – Mark Wagner May 11 '18 at 19:24
@glennjackman I like the script idea and have already attempted that; however I am using CentOS 7 and echo is immune to that as it is a shell builtin function $man builtin – syntencoist May 22 '18 at 21:35
@MarkWagner CentOS 7 /bin/sh -> /bin/bash Thanks for the feedback on that – syntencoist May 22 '18 at 22:05
@glennjackman Thanks! I just tried this as sh is actually bash on my system and it worked exactly as you suggested! – syntencoist May 22 '18 at 22:05
Bash operates differently when invoked as sh - documented in the manual – glenn jackman May 22 '18 at 22:18

linux sh -c replace echo not working

0 Answers0