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I'm a bit confused on how to calculate IPv6 numbering. I have a /32 now and a VPN client that wants 6 x /48 from that /32. Could someone please simplify on how I can determine the points of the /32 for the request? I tried a subnet calculator online but not quite getting a grip on this. IPv4 is a piece of cake compared to numbering IPv6.

Thanks.

Cazzette
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    Really, you just aren't used to it. IPv6 addressing is much easier than IPv4 addressing. The size of the addresses mess with people's heads, but having a single subnet size makes things easy. – Ron Maupin Jun 07 '16 at 03:19

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You will need to delegate individual /48s. Assuming your /32 is 2001:DB8::/32 your zone is 8.b.d.0.1.0.0.2.ip6.arpa. Reverse zones are done by dotted nibbles. That is why recommended sub-delegations are a /56 or a /48. This yields 256, and 65356 /64 subnets respectively.

If you assign 6 zones starting with 2001:DB8:1234/48, you would need to delegate the relative addresses 4.3.2.1 through 9.3.2.1

It appears your clients are requesting the capability to create 393216 subnets. Each network segment requires a /64 subnet. Each device will have one or more /128 addresses. Normally a device on the network segment (usually the router) will announce the applicable /64 subnet. In place of DHCP, devices can self-configure based on the announced subnet. It is still possible to assign fixed IPv6 addresses for devices such as servers, routers, and printers. Each /64 subnet has about 2^64 (18,446,744,073,709,551,616) addresses available for devices.

BillThor
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