Why does this RewriteRule in httpd not work?

Question

I tried to set this RewriteCond in httpd 2.4.4:

...
RewriteCond expr "%{QUERY_STRING} =~ /welcome/"
RewriteRule ^(.*)$ %1\.html

So, if I visit https://localhost/?welcome , for example, I should see the page https://localhost/welcome.html.

Instead, it returns a 500 Internal Server Error. Why?

The error log reads:

Request exceeded the limit of 10 internal redirects due to probable configuration error. Use 'LimitInternalRecursion' to increase the limit if necessary. Use 'LogLevel debug' to get a backtrace.

@PascalSchmiel Request exceeded the limit of 10 internal redirects due to probable configuration error. Use 'LimitInternalRecursion' to increase the limit if necessary. Use 'LogLevel debug' to get a backtrace. — sl34x, Jun 06 '13 at 11:15

Pascal Schmiel · Accepted Answer · 2013-06-06T11:44:02.727

0

Try:

RewriteCond %{QUERY_STRING}  (welcome)
RewriteRule ^.*$ %1.html

This replaces the %1 with the matching group from the RewriteCond. Because you are using here a static string you can just use:

RewriteCond %{QUERY_STRING}  welcome
RewriteRule ^.*$ welcome.html

edited Jun 06 '13 at 11:44

answered Jun 06 '13 at 11:24

Pascal Schmiel

1,738
12
17

I understand, but it redirects me on /.html not /welcome.html. Why is that? – sl34x Jun 06 '13 at 11:27
tried this on my own and edited my answer. – Pascal Schmiel Jun 06 '13 at 11:44
and if I use a dynamic string? – sl34x Jun 06 '13 at 11:53
Then you can use the expression you want in your RewriteCond, put it in brackets an reference to it using %1 - exactly like in the first example - but use some expression instead of "welcome" – Pascal Schmiel Jun 06 '13 at 12:35
Yes, but i meant concatenate the %1 and some other string, such as %1pageoftoday . How could i do? – sl34x Jun 06 '13 at 14:00
exactly as you did it in your comment :) - %1pageoftheday.html - or whatever – Pascal Schmiel Jun 06 '13 at 14:19
but it doesn't work anyway. I tried `RewriteRule ^(.*)$ $1` for get welcome.html when the query contains "welcome" . It returns `You don't have permission to access /.html on this server.` – sl34x Jun 06 '13 at 14:38
Don't mix up $1 and %1 - $1 refers to the brackets from your RewriteRule. What you want is the content from the brackets from your RewriteCond - that is %1 – Pascal Schmiel Jun 06 '13 at 14:41
oh,excuse-me i wrote %1 , but here i reported badly. Anyway it doesn't work. – sl34x Jun 06 '13 at 14:42
excuse-me, this is the line `RewriteRule ^(.*)$ %1.html ` – sl34x Jun 06 '13 at 14:42
how does your current ruleset looks like and what do you want to achieve? – Pascal Schmiel Jun 06 '13 at 14:43
i always get `You don't have permission to access /.html on this server` – sl34x Jun 06 '13 at 14:43
Then: `RewriteCond expr "%{QUERY_STRING} =~ /welcome/" RewriteRule ^(.*)$ %1.html` – sl34x Jun 06 '13 at 14:55
I want that when i type `https://localhost/?welcome` it returns `https://localhost/welcome.html`, but in a dynamic way, not by writing in the rewriterule directly `welcome.html` – sl34x Jun 06 '13 at 14:56
you have to put "welcome" into brackets to use it as a reference "RewriteCond %{QUERY_STRING} (welcome)" – Pascal Schmiel Jun 06 '13 at 14:57
ok,can i reference to a regex such as `(/regex/)` with %1? – sl34x Jun 06 '13 at 14:58
yes, you can - but as far as i know you don't need the slashes. – Pascal Schmiel Jun 06 '13 at 15:00
but if i try `(welcome$)` , so that the query must end with welcome, it accept also `?welcomeword` and apply the rule. How can I solve this last problem,please? – sl34x Jun 06 '13 at 15:08
Put the $ outside the brackets - that works for me: (welcome)$ – Pascal Schmiel Jun 06 '13 at 15:13

Why does this RewriteRule in httpd not work?

1 Answers1