Grep first number value from quota -u

Question

I would like to get first number from:

[root@nowosci /]# quota -u testclient
Ograniczenia dyskowe user testclient (uid 7798):
System plików   bloki miękki  twardy  pobł.   pliki miękki  twardy  pobł.
/dev/root  100256  51200000 51200000              34       0       0

So it will return just 100256

So far I went to this:

quota -u testclient | grep -Eo '[0-9]{6,10}'                          
100256
51200000
51200000

score 2 · Accepted Answer · answered Apr 25 '13 at 11:00

2

How about

quota -u testclient | tail -1 | awk '{print $2}'

answered Apr 25 '13 at 11:00

MadHatter

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Good. Umm, feel free to accept the answer, then, by clicking the tick outline next to it. My apologies if you are already familiar with the practice! – MadHatter Apr 25 '13 at 11:05

score 2 · Answer 2 · answered Apr 25 '13 at 11:08

2

Another way of doing it :)

quota -u testclient | awk '/\/dev\/root/ {print $2}'

answered Apr 25 '13 at 11:08

Danie

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This one is preferable as it specifies the desired mount point. – SmallClanger Apr 25 '13 at 11:16

Grep first number value from quota -u

2 Answers2