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I have set auto-completion in my .bashrc as follows: 

complete -W "$(echo `cat ~/.ssh_complete`;)" scp

but this ONLY used the words given in the file ~/.ssh_complete. How is it possible to extend the definition so tab-completion on scp also uses the names of files in the local directory.

A simple solution to my problem would do (filenames AND words in wordlist), I do not require tab-completion to recognize the format/details of the actual scp command. Again: I want the tab-completion to show the names of the files in the current directory AND to show the entries given in the file ~/.ssh_complete.

When there is a new suggestion I edit the file .bashrc, source it, and try the tab-completion on scp again.

Alex
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2 Answers2

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As documented, you can combine the two with:

complete -o <comp-options> -W "$(cat ~/.ssh_complete)" scp

Where <comp-options> allows you to specify which type of behaviour you want.

I got rid of the ridiculous UUoC and echo for you.

adaptr
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  • Thanks for your answer, but the behavior is not as expected. When I type `scp ` and press TAB once, it completes to `scp /home/alexander/.ssh_complete`. I was expecting to see the list of files from the current directory AND the words in the given wordlist, not the name of the wordlist (I used `filenames` for the `comp-options`). – Alex Jan 16 '13 at 10:32
  • My bad; answer edited to correct the wordlist – adaptr Jan 16 '13 at 10:33
  • Now only the word in the wordlist are taken into account for tab completion. But none of the files in the current directory. – Alex Jan 16 '13 at 10:38
  • As documented, -o only applies "if the compspec generated no matches". Filesystem completion seems to go last, except in the case of `plusdirs`. Why not add an -F that produces a glob of the CWD ? – adaptr Jan 16 '13 at 10:52
  • have you ran: ". /etc/bash_completion" before that (assuming is a Debian like distro) – jet Jan 16 '13 at 11:13
  • @jet: In a different case it work without running `. /etc/bash_completion` before. I just added the `complete` command to my `.bashrc` and sourced it. @adapt: The option `-F` does not make sense, as this is used to set a function. – Alex Jan 16 '13 at 16:17
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ok if you write a function as below

function _scp_complete
{

 COMPREPLY=""
 COMPREPLY+=( $(cat ~/.ssh_complete ) )
 COMPREPLY+=( $( ls ) )

}

then 

complete -F _scp_complete scp

the -F to complete means run the function indicated (_scp_complete) then use the array COMPREPLY with each element as one completion

In the function I reset COMPREPLY to be blank Then I cat out the ~.ssh_complete ( each line becomes one element of COMPREPLY ) then add in the output of ls.

peteches
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  • Your answer is almost the solution. As you can copy only files, I modified the line listing the directory to list only files: `COMPREPLY+=( $( find . ! -name . -prune -type f ) )`. Now I am happy... – Alex Jan 23 '13 at 06:21