How do I get the exit code of a process that's piped to tee?

Question

I have bash code like this (Mac OS X):

foo.sh | tee foo.log echo $?

The problem is that $? contains the exit code of tee and not the exit code of foo.sh. How do I get the exit code of foo.sh?

http://stackoverflow.com/questions/6871859/piping-command-output-to-tee-but-also-save-exit-code-of-command — Devdas, Aug 12 '12 at 18:39

score 7 · Answer 1 · answered Aug 12 '12 at 18:36

7

The environment variable $PIPESTATUS is an array of exit statuses for all processes in a pipeline.

answered Aug 12 '12 at 18:36

bluesmoon

291
1
3
8

Why'd you ask the question if you know the answer? – phemmer Aug 12 '12 at 19:36
2

Probably for the same reason there's a button to "answer your own question". – Skaperen Aug 12 '12 at 20:03
@Patrick I didn't know the answer when I asked the question, but did some more digging and found it. – bluesmoon Aug 13 '12 at 00:44

score 3 · Answer 2 · answered Aug 12 '12 at 18:39

3

Also use a subshell:

tm@hoegaarden:~$ cat foo.sh
#!/bin/bash

echo "stuff and junk"

exit 123
tm@hoegaarden:~$ (./foo.sh ; echo $? > ./retval ) | tee output
stuff and junk
tm@hoegaarden:~$ cat retval 
123

answered Aug 12 '12 at 18:39

Tom Maher

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1

This is more portable (not specific to `bash`) - hence upvote. – FooF Aug 14 '12 at 08:45

How do I get the exit code of a process that's piped to tee?

2 Answers2