I want to cut some portions of binary file starting from a particular pattern and ending at a particular pattern.How do I do that in linux using bash.Can this be done using sed or awk?
I have a file like given below.
bd=0x422e90e0ff4abc00 pad=0x82 offset=0x05 dst=00:0d:bc:03:6d:80 src=00:50:a2:df:e8:1c etype=0x0800 ip: version=4 headerwords=5 tos=32 length=142 ip: id=201 flags=0x2 fragmentoffset=0 ip: ttl=117 protocol=6 checksum=0x0000 ip: sourceaddress=36.190.253.236 ip: destinaddress=125.182.162.162 bd=0x422e90e0ff61f000 pad=0x92 offset=0x19 dst=00:50:a2:df:e8:1c src=00:0d:bc:03:6d:80 etype=0x0800 ip: version=4 headerwords=5 tos=0 length=40 ip: id=11084 flags=0x2 fragmentoffset=0 ip: ttl=62 protocol=6 checksum=0x0000 ip: sourceaddress=125.182.162.162 ip: destinaddress=36.190.253.236 bd=0x422e90e0ff6bb900 pad=0xb8 offset=0x06 dst=00:50:a2:df:e8:1c src=00:0d:bc:03:6d:80 etype=0x0800 ip: version=4 headerwords=5 tos=0 length=40 ip: id=15720 flags=0x2 fragmentoffset=0 ip: ttl=62 protocol=6 checksum=0x0000 ip: sourceaddress=125.182.162.162 ip: destinaddress=36.190.253.236 bd=0x422e90e0ffbe9a00 pad=0xbb offset=0xc5 dst=00:50:a2:df:e8:1c src=00:0d:bc:03:6d:80 etype=0x0800 ip: version=4 headerwords=5 tos=0 length=186 ip: id=15722 flags=0x2 fragmentoffset=0 ip: ttl=62 protocol=6 checksum=0x0000 ip: sourceaddress=125.182.162.162 ip: destinaddress=36.190.253.236
I need to cut this file from bd=0x422e90e0ff61f000 to bd=0x422e90e0ffbe9a00.Can this be done using sed or awk.