nginx: How to write regex to split URL into host and "everything else"?

Question

I want to map

https://www.example.com/Something/SomethingElse/

to

https://www.example.com/index.php?/Something/SomethingElse/

So far I understood that I need the location directive in nginx and use the try_files inside, something like this:

location ~ *???* {
  try_files $uri $uri/ /index.php?$1;
}

Now, the question is: how do I write the regular expression *???* to split URL, so I get the /Something/SomethingElse/ back (into $1)? Is it possible?

Perhaps, there is an easier way? nginx variable?

Welcome to ServerFault. You may use `request_uri` that contains "everything else" (excluding the host). Ref: https://nginx.org/en/docs/http/ngx_http_core_module.html#var_request_uri . — Pothi Kalimuthu, Mar 24 '23 at 02:32
@PothiKalimuthu Perhaps I am doing something wrong, but using `$request_uri` results in "rewrite or internal redirection cycle while internally redirecting to "/index.php"". How do I write it properly? — Александр Кулагин, Mar 24 '23 at 03:02
`location / { try_files $uri $uri/ /index.php?$request_uri`. Please post your full configuration to understand the redirection issue better. — Pothi Kalimuthu, Mar 24 '23 at 07:04
@PothiKalimuthu Can you post this as answer, so I can accept it? — Александр Кулагин, Apr 05 '23 at 14:38
Sorry about the delay. I wasn't available lately. Posted my reply as an answer. Thanks. — Pothi Kalimuthu, Apr 10 '23 at 08:26

score 1 · Accepted Answer · answered Apr 10 '23 at 08:25

The variable $request_uri that contains all parts of URL excluding the host (and the scheme - http or https). So, the solution is to use the following code (or something similar)...

location / {
   try_files $uri $uri/ /index.php?$request_uri
}

We have a similar variable in Nginx named $uri. It is not recommended to use it as it can change its value during the run time.

nginx: How to write regex to split URL into host and "everything else"?

1 Answers1