getting the last two tokens in batch script for command

Question

I have a file name with fullpath and want to get the filename and the parent directory of the file.How can I parse this in batchscript?

e.g for /f "tokens=4,5 delims=\" %%a in ("F:\mydata\WebLogs\MyServerName001\u_ex100206.log")

in the above line token 4 is the servername and 5 is the filename.But this will not be always 4 and 5.So how can I get the last two tokens in a batch script?because in my scenario the filename will be the last token and the server name will be the token before that.

score 2 · Answer 1 · answered May 10 '12 at 14:22

The post pointed to by Helvick is over the top. Here is a simple way to get the parent dir (or the parent's parent dir, etc):

for /D %%I in ("F:\mydata\WebLogs\MyServerName001\u_ex100206.log") do (
   echo filename=[%%~nxI]
)
for /D %%I in ("F:\mydata\WebLogs\MyServerName001\u_ex100206.log\..") do (
   echo parent dir=[%%~nxI]
)
for /D %%I in ("F:\mydata\WebLogs\MyServerName001\u_ex100206.log\..\..") do (
   echo parent's parent dir=[%%~nxI]
)

... etc. The file does not need to exist.

score 0 · Accepted Answer · edited May 23 '17 at 11:33

0

Use %~nxI for the filename and use the code from the selected answer in this stackoverflow post for the parent folder.

edited May 23 '17 at 11:33

Community

1

answered Feb 11 '10 at 21:06

Helvick

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you should at least clarify what %~nxl means, perhaps with an example and some output - its not necessarily obvious. I assume you actually mean %~nxa? – jheriko Aug 21 '12 at 12:00

getting the last two tokens in batch script for command

2 Answers2