why "grep -v" or "tail -f" stop my program's output?

Question

I have a server for Euro Truck Simulator 2 which is called by the following command:

LD_LIBRARY_PATH='$ORIGIN/../../linux64' eurotrucks2_server

When the server is running, sometimes I get these lines in console (and I'd like to hide them):

src/steamnetworkingsockets/clientlib/steamnetworkingsockets_sdr_common.h (564) : m_pServer->m_nReplyTimeoutsSinceLastRecv == 0

But whenever I append a | grep -v "Timeout" or | grep -v "steamnetworkingsockets", the server output is truncated at precisely this line:

Setting breakpad minidump AppID = 227300

I also tried the --line-buffered option for grep without luck and also removing grep and using | tail -f has the same result..

Here's the whole output: https://paste.debian.net/hidden/290d8573/

Thanks

score 0 · Answer 1 · answered Dec 20 '22 at 17:36

0

The | only catches the standard output (stdout) stream; these messages are going to the standard error (stderr) stream. Using grep to hide the stderr messages is a XY problem.

Solution to the Y problem

To grep both at the same time you need to forward stderr stream to stdout with 2>&1, e.g.,

eurotrucks2_server 2>&1 | grep -v "Timeout"

Solutions to the X problem

Discard stderr output with 2>/dev/null, e.g.,
```
eurotrucks2_server 2>/dev/null
```
Forward (append) stderr output to a log file with 2>>/path/to/error.log, e.g.,
```
eurotrucks2_server 2>>/var/log/eurotrucks2_server_error.log
```

answered Dec 20 '22 at 17:36

Esa Jokinen

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I'm sorry but it still stops at the same point. – roughnecks Dec 20 '22 at 18:11
this seems to work: 2> >(grep -v "Timeout"). Still waiting a bit to see if something (which shouldn't) shows up. – roughnecks Dec 20 '22 at 19:02
yeah, not working still, I see all of the content which should be hidden. – roughnecks Dec 21 '22 at 12:45

why "grep -v" or "tail -f" stop my program's output?

1 Answers1

Solution to the Y problem

Solutions to the X problem