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What I want in the following command is to find particular files and move them to the other directories while appending ".log" to the destination filename.

find /src/dir/ -type f -mtime +3 -exec mv {} /dst/dir/`basename {}`.log \;

But it fails because the basename command enclosed in the backticks does not operate properly. $(basename {}) has similar result too.

mv: cannot move /src/dir/foo to /dst/dir//src/dir/foo.log: No such file or directory

Any idea would be appreciated.

aschkant
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1 Answers1

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That's because the shell sees the `basename {}` or $(basename {}) before it handles the arguments to find and processes them. Write a script that does what you want and run it with -exec instead.

find ... -exec myscript {} \;

where myscript is something like

#! /bin/sh
mv "$1" /dst/dir/$(basename "$1").log

You can invoke the shell for each file found, so the following is also possible:

find ... -exec bash -c 'mv "$1" "$(basename "$1").log"' -- {} \;

But test such a solution properly to be sure quoting and escaping works correctly.

choroba
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  • Thanks @choroba for sharing. Since the line is a part of a script itself, I wonder if I could just simply add arguments to the -exec or totally in a single line to have the work done. – aschkant Jun 28 '21 at 13:31
  • You can add arguments, but you can't use shell syntax on them - unless you try to write something like `-exec bash -c 'mv "$1" "$(basename "$1").log"' -- {} \;` – choroba Jun 28 '21 at 13:45