Farragut, Iowa
Farragut is a city in Fremont County, Iowa, United States. The population was 490 at the time of the 2020 census.
Farragut, Iowa | |
|---|---|
Location of Farragut, Iowa | |
| Coordinates: 40°43′12″N 95°28′51″W | |
| Country | United States |
| State | Iowa |
| County | Fremont |
| Area | |
| • Total | 0.40 sq mi (1.04 km2) |
| • Land | 0.40 sq mi (1.04 km2) |
| • Water | 0.00 sq mi (0.00 km2) |
| Elevation | 961 ft (293 m) |
| Population (2020) | |
| • Total | 490 |
| • Density | 1,221.95/sq mi (471.76/km2) |
| Time zone | UTC-6 (Central (CST)) |
| • Summer (DST) | UTC-5 (CDT) |
| ZIP code | 51639 |
| Area code | 712 |
| FIPS code | 19-26985 |
| GNIS feature ID | 2394751 |
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