Cleveland, Utah
Cleveland is a town in Emery County, Utah, United States. As of the 2010 census, the town population was 464, down from 508 at the 2000 census.
Cleveland, Utah | |
|---|---|
Cleveland as seen from the south | |
Location in Emery County and the state of Utah | |
Location of Utah in the United States | |
| Coordinates: 39°20′53″N 110°51′19″W | |
| Country | United States |
| State | Utah |
| County | Emery |
| Settled | 1885 |
| Named for | Grover Cleveland |
| Area | |
| • Total | 0.86 sq mi (2.24 km2) |
| • Land | 0.86 sq mi (2.24 km2) |
| • Water | 0.00 sq mi (0.00 km2) |
| Elevation | 5,722 ft (1,744 m) |
| Population (2010) | |
| • Total | 464 |
| • Estimate (2019) | 440 |
| • Density | 508.67/sq mi (196.39/km2) |
| Time zone | UTC-7 (Mountain (MST)) |
| • Summer (DST) | UTC-6 (MDT) |
| ZIP code | 84518 |
| Area code | 435 |
| FIPS code | 49-14070 |
| GNIS feature ID | 1426712 |
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