tibble could refer to an R class (tbl_df class), which is an improved data frame with stricter checking and better formatting. tibble could also refer to an R package providing functions to create and manipulate a tibble.
Questions tagged [tibble]
1309 questions
0
votes
1 answer
Vector from tibble has length 0
I have a tibble ('df') with
> dim(df)
[1] 55 144
of which I extract a vector test <- c(df[,39]). I would expect the following result:
> length(test)
[1] 55
as I basically took column 39 from my tibble. Instead, I get
> length(test)
[1] 1
Now,…
Lukas
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1 answer
Reorder all strings in a Column of a Dataframe R
I'm trying to reorder a string in a dataframe for all of the values in a column.
I have values such as:
F123/1K
F234/2Q
F678/8W
and I want it to look like:
K1231
Q2342
W6788
Is there a way to change all the strings at once rather than the crude…
MaskedMonkey
- 107
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- 6
0
votes
2 answers
R Tibble/Dataframe to JSON where the key is the first column?
I have a tibble/dataframe that look like this:
aspect Col1 Col2 Col3 Col4
ac1 0 2.874891e-05 0.0089479233 -0.0603030498
ac2 0 1.666263e-06 0.0057062434 0
ac3 0 -1.146331e-06 0.0171818879 0
ac4…
SteveS
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0
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2 answers
convert lists of vectors in just one tibble data frame
I have two lists. Each of them with many vectors (around 500) of different lengths and I would like to get a tibble data frame with three columns.
My reproducible example is the following:
> a
[[1]]
[1] 1 3 6
[[2]]
[1] 5 4
> b
[[1]]
[1] 3…
Citizen
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- 15
0
votes
1 answer
How to keep all variables using sapply?
I have a tbl (EU_28), the head of which looks like this:
# A tibble: 5 x 22
`Member State` `1997` `1998` `1999` `2000` `2001` `2002` `2003` `2004` `2005` `2006` `2007`
…
geoffest
- 39
- 6
0
votes
1 answer
Tibble/Data_frame is not rounding using mutate_if()
I've got a tibble with similar characteristics to this:
set.seed(123)
df <- tibble(
x = sample(LETTERS[1:3],10,T),
y = rdunif(10,7.5),
z = rdunif(10,7.5)
)
Which yields:
# A tibble: 10 x 3
x y z
1 A …
elliot
- 1,844
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0
votes
1 answer
View in RStudio a table with crossed data of two labelled of a tibble
If I have a data frame (or a tibble) df as the following:
x <- c(2,2,2,1,1,2,3)
y <- c(5,5,4,5,4,4,5)
df <- data.frame(x,y)
Then, if I cross data with the instruction table(df$x,df$y) I get a matrix form:
4 5
1 1 1
2 2 2
3 0 …
iago
- 2,990
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0
votes
1 answer
Unnesting lists of different depth in a tibble
I've got a tibble that has nested lists of different depths in different columns. Each list has only one value in it or is NULL. How do I extract these into a normal tibble/dataframe with row and column single values.
I can't get purrr:map_* to…
Scott Bell
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- 11
0
votes
1 answer
Efficient method to add a column to a listcolumn in r
How can I create a new column within a listcolumn? I can only do it by mutating into a new listcolumn.
Moreover, I find that the double mutation below is quite slow compared to the other methods. Does mutate add a lot of…
Misha
- 3,114
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- 39
- 60
0
votes
1 answer
Read a set of files into a matrix in R
I am trying to read a set of tab separated files into a matrix or data.frame. For each file I need to extract one column and then concatenate all the columns into a single matrix keeping both column and row names.
I am using tidyverse (and I am…
ftabaro
- 136
- 11
0
votes
1 answer
Set an option in the R tibble package
The tibble package at version 1.4.2 has options which are listed in the documentation under tibble-options. For example, one such option is tibble.max_extra_cols which defaults to 100.
How does one access and set these options?
peter2108
- 5,580
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0
votes
1 answer
R: Which is the tidy way to apply a function over various columns of each row of a data frame?
I would like to apply a function to all rows of a data frame where each application the columns as distinct inputs (not like mean, rather as parameters).
I wonder what the tidy way is to do the following:
# Data
successes <-…
Richi W
- 3,534
- 4
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- 39
0
votes
1 answer
how can I ignore a character variable in a comparison operator on a tibble?
I have a tibble (dataframe) and I would like to select numeric elements greater than some number (e.g., 20) and update them to a new value (e.g., 0) like this:
mtcars_tbl <- as_tibble(rownames_to_column(mtcars))
mtcars_tbl[mtcars_tbl > 20] <-…
sometimes_sci
- 183
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0
votes
1 answer
R tibble error when training
I'm training a model with Caret package. The training table if fine and I don't do any changes to it.
Why then am I getting the Setting row names on a tibble is deprecated. error?
mRiddle
- 214
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0
votes
2 answers
R - Appending column to data frame. Match by year.
New to R.
Brain size of pea.
Suppose I have two separate data frames.
df1 = tibble(
date = as.Date(c("1990-10-01", "1991-11-01", "1992-11-01")),
wage = c(4, 5, 6)
)
df2 = tibble(
date = as.Date(c("1990-01-01", "1991-01-01", "1992-01-01")),
…
ixodid
- 2,180
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