php use array as array_map first argument

Question

I can't kind of make out the first return statement, can anybody help to explain how it works? the array_map accept a function for the first arg, but here is an array. and how does array(&$this, '_trimData') work? thanks for explaining.

private function _trimData($mParam)
{       
    if (is_array($mParam))
    {
        return array_map(array(&$this, '_trimData'), $mParam);
    }

    $mParam = trim($mParam);

    return $mParam;
}

score 3 · Accepted Answer · answered Jan 08 '12 at 16:52

3

This is a recursive function. _trimData calls itself if the parameter passed to it was an array.

array(&$this, '_trimData') is a callback to the current object's method _trimData.

The entire method could really be replaced with:

private function _trimData($mParam)
{ 
    array_walk_recursive($mParam, 'trim');
    return $mParam;
}

answered Jan 08 '12 at 16:52

Got it,,,your function is much easier to understand. thanks for the explanation. – bingjie2680 Jan 08 '12 at 16:59

score 1 · Answer 2 · answered Jan 08 '12 at 16:53

1

It is callback: $this->_trimData() (_trimData of object $this)

answered Jan 08 '12 at 16:53

RiaD

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score 0 · Answer 3 · answered Jul 06 '18 at 18:50

A bit further of an explanation about how array(&$this, '_trimData') acts as a callback, despite looking like an array:

A PHP function is passed by its name as a string... A method of an instantiated object is passed as an array containing an object at index 0 and the method name at index 1. PHP: Callbacks/Callables

So in this case, the object is &$this and the method is _trimData, and making it into an array is one way PHP allows you to pass it as a callback into array_map.

php use array as array_map first argument

3 Answers3