illegal start of simple expression in if-statement

Asked Sep 16 '22 at 09:10

Active Sep 16 '22 at 21:10

Viewed 44 times

I have some issues with scala. I got this error when I run scalastyle

illegal start of simple expression

This question is linked with other questions about scalastyle illagal error but I tried all solutions proposed but nothing has fixed the error.

Here is the piece of my code And the error is located in the if-statement at netexr function.

case class EXT (ev: Seq[String])
val schema = StructType(Seq(
        StructField("label", DoubleType)
    ))
def hasVis(ev: Seq[String]): Boolean = ev.toSet.exists(videoV.contains)
def hasCom(ev: Seq[String]): Boolean = ev.toSet.exists(videoC.contains)
def nexter: EXT => Seq[Row] = (extension: EXT) => Seq(new GenericRowWithSchema(
    Array(if (hasVis(extension.ev) && hasCom(extension.ev)) 1.0 else 0.0), schema))

Thank you for your help

edited Sep 16 '22 at 21:10

Levi Ramsey

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asked Sep 16 '22 at 09:10

Marc

1

Try using an intermediate assignment of the `if` statement to a `val` in the method and see if it goes away. – Alin Gabriel Arhip Sep 16 '22 at 11:50

illegal start of simple expression in if-statement

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