I have compiled the very simple program
$ cat main.cpp
#include <iostream>
int main() {
uint64_t val=1;
// val = htobe64(val);
std::cout << val << std::endl;
}
$ g++ -g main.cpp -o a.out
When I debug it using cgdb I get the following:
$ cgdb a.out
But when I uncomment the line // val = htobe64(val)
something strange happens:
$ cat main.cpp
#include <iostream>
int main() {
uint64_t val=1;
val = htobe64(val);
std::cout << val << std::endl;
}
$ g++ -g main.cpp -o a.out
$ cgdb a.out
Uncommenting this single line causes cgdb to start showing the splash screen and when I type start
as in the screenshot it only gives me assembler code (before cgdb started directly showing the source code and not its splash screen). Furthermore somehow the file path /home/user/byteswap.h
appears in the screenshot, but this file does not exist (In this example user
is was my username and /home/user
my working directory).
Can someone tell me what is happening here and what I can do to be able to debug a program that is calling htobe64
, i.e. how to achieve that cgdb will show me the source code as in the first example at the top?
Here are the tool versions:
$ cgdb --version
CGDB 0.7.1
Copyright 2002-2019 Bob Rossi and Mike Mueller.
CGDB is free software, covered by the GNU General Public License, and you are
welcome to change it and/or distribute copies of it under certain conditions.
There is absolutely no warranty for CGDB.
$ gdb --version
GNU gdb (Debian 8.2.1-2+b3) 8.2.1
Copyright (C) 2018 Free Software Foundation, Inc.
License GPLv3+: GNU GPL version 3 or later <http://gnu.org/licenses/gpl.html>
This is free software: you are free to change and redistribute it.
There is NO WARRANTY, to the extent permitted by law.
$ g++ --version
g++ (Debian 11.2.0-10) 11.2.0
Copyright (C) 2021 Free Software Foundation, Inc.
This is free software; see the source for copying conditions. There is NO
warranty; not even for MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.