Python argparse fails when the script run without preceding py -2 or -3

Asked Jun 02 '21 at 12:19

Active Jun 06 '21 at 05:51

Viewed 86 times

My python code is:

# my_script.py

import argparse
parser = argparse.ArgumentParser()
parser.add_argument("-v", "--verbose", help="increase output verbosity",
                    action="store_true")
args = parser.parse_args()
if args.verbose:
    print("verbosity turned on")

My default python is Python 3.7.4 (also python 2 is installed on my PC). When I run this script from Windows command line this way:

py -2 my_script.py

or this way:

py -3 my_script.py

The script works fine. But when I run this way:

my_script.py

I get the next error:

usage: my_script.py [-h] [-v]
my_script.py: error: unrecognized arguments:

Why? I always run all my python scripts without preceding py and it works (they do not include argparse module)

Can you please help - why python script that contains arparse does not run without preceding py?

edited Jun 06 '21 at 05:51

asked Jun 02 '21 at 12:19

Halona

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Try typing 'where my_script' to see if you are accidentally running another version of my_script.py that is located on your path. – vintastic Jun 02 '21 at 12:53
1

Is `my_scirpt.py` the actual output or is it a typo? – Axe319 Jun 02 '21 at 16:13
Hi Axe319, it's a typo - fixing – Halona Jun 06 '21 at 05:51
It is likely that the command associated with `.py` in the registry is introducing the error. – BoarGules Jun 06 '21 at 08:12

Python argparse fails when the script run without preceding py -2 or -3

0 Answers0