Is there a python standard function to parse a string into an argv list exactly like bash does, in Python?

Question

Consider the following string:

./kmux.py  -r 'messenger.* xx'

If kmux.py is a python script, and the string above was given to bash as an argument, then sys.argv will be the following list:

["./kmux.py", "-r", "messenger.* xx"]

Is there a standard python function that will take the first string and turn it into the array?

I could manually replicate bash's logic in Python to take the original string and turn it into this array, but I am curious about whether such a function already exists.

Does [`shlex.split`](https://docs.python.org/3/library/shlex.html#shlex.split) work for you? — awesoon, Dec 19 '20 at 07:23

score 2 · Accepted Answer · answered Dec 19 '20 at 07:26

2

Use the default shlex package like so:

import shlex
shlex.split("'./kmux.py  -r 'messenger.* xx'")

answered Dec 19 '20 at 07:26

hazrmard

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Is there a python standard function to parse a string into an argv list exactly like bash does, in Python?

1 Answers1