How to define exception to be thrown through ref in Apache Camel

Question

Have to throw an exception in my camel route defined in XML. Found throwException statement available from Camel 2.3 which looks like:

 <throwException ref="forced"></throwException>

However, I don't know how to define forced exception class to be thrown. Since same exception could be thrown couple of times with different exception messages - would be good to know if throwException has some other form of definition so exception class and exception message are defined in-place.

score 19 · Accepted Answer · edited Mar 12 '13 at 05:01

19

The ref is just a reference to a so you can do

<bean id="forced" class="java.lang.IllegalArgumentException">
   <constructor-arg index="0" value="This is forced"/>
</bean>

<camelContext ...>
  ...
</camelContext>

edited Mar 12 '13 at 05:01

Manglu

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answered Apr 30 '11 at 07:00

Claus Ibsen

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You can also look in the src/test/java directory of the source code of camel-spring, to find examples how to use in XML – Claus Ibsen Apr 30 '11 at 07:02

Enigo · Answer 2 · 2016-05-19T18:06:45.250

15

Since version 2.16.0 there is more elegant way to do it, with optional exception message:

<route>
     <throwException exceptionType="java.lang.IllegalArgumentException" message="illegal argument found"/>
</route>

edited May 19 '16 at 18:06

answered May 19 '16 at 13:01

Enigo

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How to define exception to be thrown through ref in Apache Camel

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