How parse JSON and set as Object Model

Question

I have an API with 2 different response:

response OK

{ "name": "test" }

response KO

[
    {
        "name_1": "test",
        "name_2": "test"
    }
]

the problem is that using Retrofit, normally, I use a model to parse results but response KO has not an array name.

How can I create a model? (I cannot change the API)

Using Retrofit can I use 2 different models? Retrofit can accepts only 1 response model... — Carlos, Jun 26 '19 at 07:31
Sure. You just need to add your second POJO to the retrofit client as you did with the first one. — philoez98, Jun 26 '19 at 07:32
Normally I use ```Call login(@Body HashMap body);``` how can I set 2 models ? — Carlos, Jun 26 '19 at 07:34
Are you using Gson to serialize /deserialize your Json data? — philoez98, Jun 26 '19 at 07:37

score 1 · Answer 1 · answered Jun 26 '19 at 07:48

So to add another POJO you can do this:


private static Gson gson = new GsonBuilder()

 .registerTypeAdapter(Model1.class, new GsonDeserializer<Model1>())


 .registerTypeAdapter(Model2.class, new GsonDeserializer<Model2>())

//or  create a POJO for the names array of Model2
.registerTypeAdapter(Model2.class, new GsonDeserializer<Names>())

Where GsonDeserializer is a custom serializer that can be defined, like:

public class GsonDeserializer<T> implements JsonDeserializer<T> {

@Override

public T deserialize(JsonElement json, Type typeOfT, JsonDeserializationContext context) throws JsonParseException {

 JsonObject el = json.getAsJsonObject();

 return new Gson().fromJson(el, typeOfT);

}

And then in your Retrofit client you just add:


retrofit = new Retrofit.Builder()

.addConverterFactory(GsonConverterFactory.create(gson))

.build();

How parse JSON and set as Object Model

1 Answers1