Real path of file string pathlib

Question

I've been searching for what seems like hours for how to get a real path in string format from a pathlib.PosixPath using pathlib.

The only solution I can find is this:

str(myPathObject.resolve())

This seems messy. Am I missing something or is this only solution that exists?

Edit:

To clarify, this is giving me a filepath /opt/digglerz/projects of type string, which is what i want. This seems a long way to do this, is there no better way?

What you are getting as output ans what you expecting? Please clarify. — Amazing Things Around You, Jun 06 '19 at 12:18
Still I am unable to get what you are looking for. Why do you think the above answer is messy or long process? — Amazing Things Around You, Jun 06 '19 at 12:27

score 2 · Answer 1 · answered Jun 06 '19 at 12:22

2

resolve() is a good idea, but the literal casting with str indeed seems a bit messy. I would go with built-in methods like as_posix() or as_uri() depending on what you want.

Understand that the concept of "real path" as you call it may be different in different situations and on different platforms.

Hope this helps!

answered Jun 06 '19 at 12:22

Bart Van Loon

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Looking at the [source code](https://github.com/python/cpython/blob/3.7/Lib/pathlib.py#L713) reveals that `as_posix()` just returns `str(self).replace(f.sep, '/')`. – mkrieger1 Jun 06 '19 at 12:25
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Why would you use `as_posix()` to convert a path to string? If you don't want a posix path, don't use `as_posix()`. Just use `str`. – Aran-Fey Jun 06 '19 at 12:32

score 1 · Answer 2 · answered Nov 20 '19 at 21:13

1

Since 3.6 the correct way to convert a Path object back into a string seems to be:

os.fspath(path)

https://docs.python.org/3/library/os.html#os.fspath

answered Nov 20 '19 at 21:13

Grumbel

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Real path of file string pathlib

2 Answers2