Future raising TypeError after wait

Question

I'm trying to optimise an expensive operation in some existing code using parallel processing. I've used concurrent.futures to do so in the past but only when they didn’t return anything.

This time I want to marshall the results, but when printing my collection I'm getting every future's status as something like <Future at 0x... state=finished raised TypeError>. Can anyone explain what I'm doing wrong?

import concurrent.futures

with concurrent.futures.ProcessPoolExecutor() as executor:

  def _future(self) -> None:
    print("here")

  futures = []
  for number in list(range(0,100)):
    future = executor.submit(_future)
    futures.append(future)

  finished = concurrent.futures.wait(futures, 5)
  print(finished)

score 13 · Accepted Answer · answered Mar 23 '19 at 15:13

Your _future function takes one parameter, and yet your executor.submit is passing no argument to it. You should pass, for example, number, as an argument to it instead:

for number in list(range(0,100)):
    future = executor.submit(_future, number)
    futures.append(future)

On the other hand, since you're naming _future's one parameter as self, it implies you intend it to be an instance of a class, in which case you should pass to it the proper instance object in your original, non-minimized code.

Ah! Yeah, I’d got confused with some existing code that was part of a class structure, this fixes my issue. Thanks! — Robin Whittleton, Mar 23 '19 at 17:40

Future raising TypeError after wait

1 Answers1