Grouping strings together in Vavr

Question

I'm trying this code below:

final Map<Word, List<Word>> tuple2s = lowercase
            .groupBy(identity());

but this creates groups of single strings, basically like doing a #split:

LinkedHashMap((lorem, List(lorem)), (ipsum, List(ipsum)), (lorem, List(lorem)), (lorem, List(lorem)), (ipsum, List(ipsum)), (dolor, List(dolor)), (sit, List(sit)), (dolor, List(dolor)), (sit, List(sit)), (dolor, List(dolor)), (elit, List(elit)))

How do I fix this? The expected value is

LinkedHashMap((lorem, List(lorem, lorem, lorem)), (ipsum, List(ipsum, ipsum)), (dolor, List(dolor, dolor, dolor)), (sit, List(sit, sit)), (elit, List(elit)))

don't you need word count? the word would be the key and the value would the number of occurrences — Adam Siemion, Jan 31 '19 at 13:28
@AdamSiemion I do, in fact, try to implement such logic but because of this part, it does not work as expected. When I used that code with `.mapValues(group -> group.size())`, it just zipped all the single words with "1"s. — Cube., Jan 31 '19 at 13:39

score 2 · Accepted Answer · answered Jan 31 '19 at 15:08

You need a correct implementation of equals and hashCode in your Word class, that is based on the string content of the word that it represents. With that in place, List.groupBy(...) will result in what you would expect. Something similar to the following will suffice.

public class Word {
    private String word;

    public Word(String word) { this.word = word; }

    @Override
    public String toString() { return word; }

    @Override
    public boolean equals(Object o) {
        if (this == o) return true;
        if (o == null || getClass() != o.getClass()) return false;
        Word other = (Word) o;
        return Objects.equals(word, other.word);
    }

    @Override
    public int hashCode() { return Objects.hash(word); }
}

Grouping strings together in Vavr

1 Answers1