<div id="displayCarousel" class="carousel slide carousel-fade" data-ride="carousel">
<div class="carousel-inner" role="listbox">
<div class="carousel-item" ng-class="{active:!$index}" ng-repeat="pics in advertimages">
<div class="view">
<span ng-repeat="x in pics.files">
<img ng-src="img/my_adverts/{{x}}" class="d-block w-100" alt="image">
</span>
<div class="mask rgba-black-light"></div>
</div>
<div class="carousel-caption">
<h3 class="h3-responsive">From:</h3>
<p>@{{pics.username}}</p>
</div>
</div>
</div>
<a class="carousel-control-prev" href="#displayCarousel" role="button" data-slide="prev">
<span class="carousel-control-prev-icon" aria-hidden="true"></span>
<span class="sr-only">Previous</span>
</a>
<a class="carousel-control-next" href="#displayCarousel" role="button" data-slide="next">
<span class="carousel-control-next-icon" aria-hidden="true"></span>
<span class="sr-only">Next</span>
</a>
</div>
$scope.advertimages is an array from the database, the array contains a column called files which is also an array. The problem I have with this is that if the files of a particular row in $scope.advertimages contains more than one image, then all the images in that row will display on a single page of the carousel.
Let me explain better. Let's assume the column 'files' of the first row of advertimages has a single image. Then the column 'files'of the second row of advertimages has three images. The single image of the first row will take a single page of the carousel, which is what I want but the problem I have is that: the three Images of the second row will be on a single page of the carousel. What I want is that: the three images of the second row should also be on different pages of the carousel.