Different XSLT processing result compared with xsltproc

Question

I'm doing XSLT processing with libxslt(plus libxml2, libexslt).
First, I did my XSLT processing with xsltproc using an XML input file like below and using MS Office's XSL file(APASixthEditionOfficeOnline.xsl). You can see the XML output like below.

XML input (input.xml)

<?xml version="1.0"?>
<b:StyleNameLocalized xmlns:b="http://schemas.openxmlformats.org/officeDocument/2006/bibliography">
    <b:Lcid>1042</b:Lcid>
</b:StyleNameLocalized>`

XSL stylesheet (APASixthEditionOfficeOnline.xsl)

<?xml version="1.0" encoding="utf-8"?>
  <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:b="http://schemas.openxmlformats.org/officeDocument/2006/bibliography">
    <xsl:output method="html" encoding="us-ascii"/>
    <xsl:template match="/">
      <xsl:choose>
        <xsl:when test="b:StyleNameLocalized">
          <xsl:choose>
            <xsl:when test="b:StyleNameLocalized/b:Lcid='1042'">
              <xsl:text>APA</xsl:text>
            </xsl:when>
          </xsl:choose>
        </xsl:when>
      </xsl:choose>             
    </xsl:template>
  </xsl:stylesheet>

XML output by xsltproc

I wrote the below code in the command line.

xsltproc APASixthEditionOfficeOnline.xsl input.xml > output.xml
And I got a text in output.xml
APA

Meanwhile, I tried to make my own xsltproc by implementing the functions of libxml2 and libxslt.

I used the same APASixthEditionOfficeOnline.xsl file, however didn't parsed the input.xml but generated XmlDocPtr in the code. Below is my code.

My Code

const xmlChar* stylesheetfile = (const xmlChar*)"APASixthEditionOfficeOnline.xsl";
xsltStylesheetPtr style = xsltParseStylesheetFile(xslfile);
xmlDocPtr doc = xmlNewDoc(BAD_CAST "1.0");
xmlNodePtr root_node = xmlNewNode(NULL, BAD_CAST "b:StyleNameLocalized");
xmlNsPtr ns =
        xmlNewNs(root_node,
                BAD_CAST "http://schemas.openxmlformats.org/officeDocument/2006/bibliography",
                BAD_CAST "b");
xmlDocSetRootElement(doc, root_node);
xmlNewChild(root_node, ns, BAD_CAST "Lcid", BAD_CAST "1042");
xmlDocPtr output = xsltApplyStylesheet(style, doc, 0);
mlChar* xmlData;
int size;
xmlDocDumpMemory(output, &xmlData, &size);

The expected result of the variable xmlData is "APA", but I got this result.

My Result
<?xml version="1.0" encoding="us-ascii" standalone="yes"?>

I want the same result of xsltproc.
Can you figure out the problem of my code?
It will be really helpful for your comment.
Thank you.

It would help if you post minimal but complete samples to allow others to reproduce the problem. So provide a minimal but complete stylesheet for which the differences occur, describe the exact command line with which you call `xsltproc`. And you might want to add a tag for the C programming language as well and show the code that outputs the result of the XSLT transformation, i.e. that produces the "My Result" line you have shown. — Martin Honnen, Nov 29 '18 at 09:20
@MartinHonnen Thank you for your advice, I edited my question and gave some detail. — BcFlower, Nov 29 '18 at 12:47

score 1 · Accepted Answer · answered Nov 29 '18 at 11:20

1

Since the result of an XSLT transformation isn't always a well-formed document and depends on xsl:output, you have to use one of the xsltSaveResultTo functions to output the result.

answered Nov 29 '18 at 11:20

nwellnhof

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I detailed the xsl code and `xsl:output` is like below `` would this be the problem? – BcFlower Nov 30 '18 at 01:37
1

Thanks, I solved the problem using `xsltSaveResultToString` :) – BcFlower Dec 04 '18 at 05:55

Different XSLT processing result compared with xsltproc

1 Answers1