Group mongodb collection and output the result as a single object

Question

Is there a way to group a collection which looks like

[
  {_id: "5bd258a7877e74059b6b65b2", year: 2017, title: "One"},
  {_id: "5bd258a7877e74059b6b65b3", year: 2017, title: "Two"},
  {_id: "5bd258a7877e74059b6b65b4", year: 2018, title: "Three"},
  {_id: "5bd258a7877e74059b6b65b5", year: 2018, title: "Four"}
]

and output the result as

{
  2017: [
    0: {_id: "5bd258a7877e74059b6b65b2", title: "One", …}
    1: {_id: "5bd258a7877e74059b6b65b3", title: "Two", …}
  ],
  2018: [
    0: {_id: "5bd258a7877e74059b6b65b4", title: "Three", …}
    1: {_id: "5bd258a7877e74059b6b65b5", title: "Four", …}
  ]
}

using mongodb aggregations? Similar to how lodash groupBy works

Akrion · Accepted Answer · 2018-10-28T02:02:16.527

You can do that with the following mongoDB aggregation:

db.collection.aggregate([{
    $group: {
      _id: "$year",
      docs: {
        $addToSet: "$$CURRENT"
      }
    }
  },
  {
    "$group": {
      "_id": null,
      "data": {
        "$push": {
          "k": {
            $toString: "$_id"
          },
          "v": "$docs"
        }
      }
    }
  },
  {
    "$replaceRoot": {
      "newRoot": {
        "$arrayToObject": "$data"
      }
    }
  }
])

You can see the result here

The idea is to group the data in a way where we can utilize $arrayToObject. First group gives you the grouped by year where the second is just prep for $arrayToObject which requires key, value object. Last thing is the $replaceRoot.

This requires MongoDB 3.6 and up due to $arrayToObject being introduced in that version. Before that you had to use $push etc.

Group mongodb collection and output the result as a single object

1 Answers1