I don't know whether it's in Scalaz/Cats (maybe, cannot guarantee that it's not there), but in principle, it does work. Here is a little demo without any dependencies that demonstrates the principle.
Assume you have these typeclasses from either Scalaz or Cats:
import scala.language.higherKinds
trait Functor[F[_]] {
def map[A, B](a: F[A])(f: A => B): F[B]
}
type Id[X] = X
implicit object IdFunctor extends Functor[Id] {
def map[A, B](a: A)(f: A => B): B = f(a)
}
implicit object OptionFunctor extends Functor[Option] {
def map[A, B](a: Option[A])(f: A => B) = a map f
}
you can then either write or find in the library a typeclass that works like the following contraption:
trait EverythingIsAlwaysAFunctor[A, B, F[_]] {
def apply(a: A): F[B]
def functor: Functor[F]
}
object EverythingIsAlwaysAFunctor {
implicit def functorIsFunctor[A, F[_]](implicit f: Functor[F])
: EverythingIsAlwaysAFunctor[F[A], A, F] = {
new EverythingIsAlwaysAFunctor[F[A], A, F] {
def apply(fa: F[A]): F[A] = fa
def functor: Functor[F] = f
}
}
implicit def idIsAlsoAFunctor[A]
: EverythingIsAlwaysAFunctor[A, A, Id] = {
new EverythingIsAlwaysAFunctor[A, A, Id] {
def apply(a: A): Id[A] = a
def functor: Functor[Id] = implicitly[Functor[Id]]
}
}
}
This thing does the following:
- If the value
A
is already of shape F[B]
for some functor F
, then uses this functor
- In all other cases, it pretends that
A
is actually Id[A]
Now you can write your DoSomething
-pimp-my-library-syntax thing with a single doSomething
method:
implicit class DoSomething[A, F[_]](a: A)(
implicit eiaaf: EverythingIsAlwaysAFunctor[A, Int, F]
) {
def doSomething: F[String] = eiaaf.functor.map(eiaaf(a))("*" * _)
}
and then it just works in all cases:
val x = Option(42).doSomething
val y = 42.doSomething
println(x)
println(y)
prints:
Some(******************************************)
******************************************