Browsersync without scss?

Question

I'm new to gulp, and I'm trying to set up browsersync without scss. all of the examples i have seen have you set it up for pre-processing sass. How can I set it to watch the plain css? Here's my gulpfile.js:

const gulp = require('gulp'),
browserSync = require('browser-sync').create(),
sass = require('gulp-sass');


// Static server & watch scss + html files
gulp.task('watch', ['sass'], function() {

browserSync.init({
server: '.'
});

gulp.watch('./assets/**/*.scss', ['sass'], browserSync.reload);
gulp.watch('./*.html').on('change', browserSync.reload);
gulp.watch('./js/**/*.js', browserSync.reload);

});

// Compile Sass into CSS & inject into browsers
gulp.task('sass', function() {
return gulp.src('./assets/**/*.scss')
.pipe(sass().on('error', sass.logError))
.pipe(gulp.dest('./css'))
.pipe(browserSync.stream());
});


// default will also watch
gulp.task('default', ['watch']);

@SLaks By the way, Ben is for Binyamin : ) So cool to meet another frum programmer — Binyamin Green, Jul 23 '18 at 22:41

score 0 · Accepted Answer · answered Jul 23 '18 at 23:55

Try this block of code. It worked for me. I don't think the sass = require('gulp-sass') is necessary, though.

const gulp = require('gulp'),
browserSync = require('browser-sync').create(),
sass = require('gulp-sass');


// Static server & watch scss + html files
gulp.task('watch', function() {

browserSync.init({
server: '.'
});

gulp.watch('./assets/*.css', browserSync.reload);
gulp.watch('./*.html').on('change', browserSync.reload);
gulp.watch('./js/*.js', browserSync.reload);

});


// default will also watch
gulp.task('default', ['watch']);

Browsersync without scss?

1 Answers1