String IO to element.etree

Question

I want to parse StringIO in form of xml with etree, hovever I have following error. Example:

import xml.etree.ElementTree
from io import StringIO

def main():
    in_mem_file = StringIO()
    in_mem_file.write('<?xml version="1.0" encoding="UTF-8"?>')
    in_mem_file.write('<tag>')
    in_mem_file.write('</tag>')
    print(in_mem_file.getvalue())
    e = xml.etree.ElementTree.parse(in_mem_file).getroot()

This raises following error:

xml.etree.ElementTree.ParseError: no element found: line 1, column 0

It works if you provide the complete XML content when creating the `StringIO` object. Using `write()` does not work. — mzjn, Jul 14 '18 at 11:51

score 3 · Answer 1 · answered Jul 16 '18 at 08:43

Provide the whole XML document when creating the StringIO object. Using write() does not work (but I don't have an explanation for that).

import xml.etree.ElementTree as ET
from io import StringIO

XML = """<?xml version="1.0" encoding="UTF-8"?>
    <tag>
    </tag>"""

in_mem_file = StringIO(XML)
tree = ET.parse(in_mem_file)

score 0 · Answer 2 · answered Jun 23 '22 at 14:24

0

You have to reset the cursor position of the StringIO object before handing it to ET:

in_mem_file = StringIO()
in_mem_file.write('<?xml version="1.0" encoding="UTF-8"?>')
in_mem_file.write('<tag>')
in_mem_file.seek(0)

answered Jun 23 '22 at 14:24

pygeneer

1
1

String IO to element.etree

2 Answers2