How to make ESLint ignore class names and methods from other files?

Question

This has probably been asked before, but I don't really know how to search for it so if it has, I am really sorry.

Say I have a file called a.js that has a class called Navigation in it, then in b.js I call that with a method inside the class called getView();

a.js

Navigation.prototype.getView = function getView(id) {
   return this.views[id]; 
};

b.js

var currentView = Navigation.getView(id);

How would I go about tell ESLint that Navigation should be ignred from the no-undef rule?

ztadic91 · Accepted Answer · 2018-03-02T13:54:48.583

1

You can try to use the globals comment inside the file you want to ignore it.

/* globals MY_GLOBAL */

edited Mar 02 '18 at 13:54

answered Mar 02 '18 at 13:45

ztadic91

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Why a comment? This is what eslint configuration is for. – Estus Flask Mar 02 '18 at 14:00
I also noticed that I can just include this in the configuration file. Either way, it's still really helpful :) – ChronixPsyc Mar 02 '18 at 15:35

score 1 · Answer 2 · edited Jun 20 '20 at 09:12

1

ESLint lints each file in isolation, so it will not resolve identifiers defined in other files. The /* exported ... */ comment and globals allow you to inform ESLint of dependencies in other files.

Note that /* exported */ has no effect for any of the following:

when the environment is node or commonjs

when parserOptions.sourceType is module

when ecmaFeatures.globalReturn is true

edited Jun 20 '20 at 09:12

Community

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answered Mar 02 '18 at 13:48

kemotoe

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How to make ESLint ignore class names and methods from other files?

2 Answers2