6

I have a table named messages containing toUser, message and status columns. I want to update all the statuses of the messages with a specific user.

So, I wrote a query like this,

Session s = DB.getSession();
s.createSQLQuery("UPDATE `message` SET `status`='0' WHERE `toUser`='3'").executeUpdate();
s.close();

But then, I was been told that updating using pure hibernate methods are more faster and efficient (I think it has to do something with the hibernate pool), like shown below.

Session s = DB.getSession();
Transaction tr = s.beginTransaction();
Criteria cr = s.createCriteria(Connection.Pojo.Message.class);
cr.add(Restrictions.eq("toUser", 3));
List<Connection.Pojo.Message> l = cr.list();
for (Connection.Pojo.Message msg : l) {
    msg.setStatus((byte) 0);
    s.update(msg);
}
tr.commit();
s.close();

So, my question is what is the fastest way to update these rows? Please provide a detailed answer if possible.

Thanks in any advice.

Roshana Pitigala
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1 Answers1

3

I think by "pure Hibernate methods" they meant using an HQL update:

Session s = DB.getSession();
s.createQuery("UPDATE message m SET m.status=:newStatus WHERE toUser=:userId")
    .setInteger("newStatus", 0)
    .setInteger("userId", 3)
    .executeUpdate();
s.close();

This approach provides performance that is equivalent to your SQL solution.

Sergey Kalinichenko
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