Copy array via memcpy

Question

I saw there are a lot of articles about memcpy but I can't find the solution for my problem. Can somebody see why the copy action doesn't work?

float MeanFilter(const volatile float *Array, volatile float Dist){
float Avg = 0.0;    // Variable used to calculate the average distance value
float Sorted[MaxDistArray]; // Array used to contain the sorted array

printf("\n");
int j;

for(j = 0; j < 20; j++){
    if(j == 10) printf("\n \t");
    printf("%d: %f, ", j+1, Array[j]);
}

memcpy(Sorted, &Array[0], sizeof(float));
Sort(Sorted);   // Sort the array of distances values

printf("\n");

for(j = 0; j < 20; j++){
    if(j == 10) printf("\n \t");
    printf("%d: %f, ", j+1, Sorted[j]);
}

What *is* the problem you are having? Can you please show us a [Minimal, Complete, and Verifiable Example](http://stackoverflow.com/help/mcve)? And also tell us what input you give, and the expected and actual output from that input. — Some programmer dude, Dec 05 '17 at 13:34
Oh and you probably should [read a `memcpy` reference](http://en.cppreference.com/w/c/string/byte/memcpy). Pay close attention to the last (the `count`) argument and what it is supposed to be. — Some programmer dude, Dec 05 '17 at 13:35
You only copy a single value; If you multiply the `sizeof(float)` with the number of floats you'd like to copy, you might get better results. — Ronald, Dec 05 '17 at 13:36

score 1 · Accepted Answer · answered Dec 05 '17 at 13:50

1

Idd @Ronald that was part of the solution

memcpy(Sorted, Array, sizeof(float)*MaxDistArray);

thx!

answered Dec 05 '17 at 13:50

NickDR92

11
5

Copy array via memcpy

1 Answers1