Get default line colour cycle

Question

I noticed when you plot that the first line is blue, then orange, then green, and so on.

Is there some way to access this list of colours? I've seen a million posts on how to change the colour cycle or access the iterator, but not on how to just get the list of colours that matplotlib cycles through by default.

Answer 1

In matplotlib versions >= 1.5, you can print the rcParam called axes.prop_cycle:

print(plt.rcParams['axes.prop_cycle'].by_key()['color'])

# [u'#1f77b4', u'#ff7f0e', u'#2ca02c', u'#d62728', u'#9467bd', u'#8c564b', u'#e377c2', u'#7f7f7f', u'#bcbd22', u'#17becf']

Or equivalently, in python2:

print plt.rcParams['axes.prop_cycle'].by_key()['color']

In versions < 1.5, this was called color_cycle:

print plt.rcParams['axes.color_cycle']

# [u'b', u'g', u'r', u'c', u'm', u'y', u'k']

Note that the default color cycle changed in version 2.0.0 http://matplotlib.org/users/dflt_style_changes.html#colors-in-default-property-cycle

Answer 2

Often, there is no need to get the default color cycle from anywhere, as it is the default one, so just using it is sufficient.

import numpy as np
import matplotlib.pyplot as plt

fig = plt.figure()
ax = fig.add_subplot(111)

t = np.arange(5)

for i in range(4):
    line, = ax.plot(t,i*(t+1), linestyle = '-')
    ax.plot(t,i*(t+1)+.3,color = line.get_color(), linestyle = ':')

plt.show()

In case you want to use the default color cycle for something different, there are of course several options.

"tab10" colormap

First it should be mentionned that the "tab10" colormap comprises the colors from the default color cycle, you can get it via cmap = plt.get_cmap("tab10").

Equivalent to the above would hence be

import numpy as np
import matplotlib.pyplot as plt

fig = plt.figure()
ax = fig.add_subplot(111)

t = np.arange(5)
cmap = plt.get_cmap("tab10")
for i in range(4):
    ax.plot(t,i*(t+1),   color=cmap(i), linestyle = '-')
    ax.plot(t,i*(t+1)+.3,color=cmap(i), linestyle = ':')

plt.show()

Colors from color cycle

You can also use the color cycler directly, cycle = plt.rcParams['axes.prop_cycle'].by_key()['color']. This gives list with the colors from the cycle, which you can use to iterate over.

import numpy as np
import matplotlib.pyplot as plt

fig = plt.figure()
ax = fig.add_subplot(111)

t = np.arange(5)
cycle = plt.rcParams['axes.prop_cycle'].by_key()['color']

for i in range(4):
    ax.plot(t,i*(t+1),   color=cycle[i], linestyle = '-')
    ax.plot(t,i*(t+1)+.3,color=cycle[i], linestyle = ':')

plt.show()

The CN notation

Finally, the CN notation allows to get the Nth color of the color cycle, color="C{}".format(i). This however only works for the first 10 colors (N in [0,1,...9])

import numpy as np
import matplotlib.pyplot as plt

fig = plt.figure()
ax = fig.add_subplot(111)

t = np.arange(5)

for i in range(4):
    ax.plot(t,i*(t+1),   color="C{}".format(i), linestyle = '-')
    ax.plot(t,i*(t+1)+.3,color="C{}".format(i), linestyle = ':')

plt.show()

All codes presented here produce the same plot.

Answer 3

The CN notation revisited

I'd like to address a new development of Matplotlib. In a previous answer we read

Finally, the CN notation allows to get the Nth color of the color cycle, color="C{}".format(i). This however only works for the first 10 colors (N in [0,1,...9])

but

import numpy as np 
import matplotlib.pyplot as plt 

t = np.linspace(0,6.28, 629)                                                      
for N in (1, 2): 
    C0N, C1N = 'C%d'%(N), 'C%d'%(N+10) 
    plt.plot(t, N*np.sin(t), c=C0N, ls='-',  label='c='+C0N) 
    plt.plot(t, N*np.cos(t), c=C1N, ls='--', label='c='+C1N) 
plt.legend() ; plt.grid() ; plt.show()                                           

gives

Answer 4

if you're looking for a quick one-liner to get the RGB colors that matplotlib uses for its lines, here it is:

>>> import matplotlib; print('\n'.join([str(matplotlib.colors.to_rgb(c)) for c in matplotlib.pyplot.rcParams['axes.prop_cycle'].by_key()['color']]))
(0.12156862745098039, 0.4666666666666667, 0.7058823529411765)
(1.0, 0.4980392156862745, 0.054901960784313725)
(0.17254901960784313, 0.6274509803921569, 0.17254901960784313)
(0.8392156862745098, 0.15294117647058825, 0.1568627450980392)
(0.5803921568627451, 0.403921568627451, 0.7411764705882353)
(0.5490196078431373, 0.33725490196078434, 0.29411764705882354)
(0.8901960784313725, 0.4666666666666667, 0.7607843137254902)
(0.4980392156862745, 0.4980392156862745, 0.4980392156862745)
(0.7372549019607844, 0.7411764705882353, 0.13333333333333333)
(0.09019607843137255, 0.7450980392156863, 0.8117647058823529)

Or for uint8:

import matplotlib; print('\n'.join([str(tuple(int(round(v*255)) for v in matplotlib.colors.to_rgb(c))) for c in matplotlib.pyplot.rcParams['axes.prop_cycle'].by_key()['color']]))
(31, 119, 180)
(255, 127, 14)
(44, 160, 44)
(214, 39, 40)
(148, 103, 189)
(140, 86, 75)
(227, 119, 194)
(127, 127, 127)
(188, 189, 34)
(23, 190, 207)