I have a SQL query
select time,t_count,sum(t_count) over (order by time) as
cumulative_t_count ,cumulative_t_count/sum(t_count) as percentage_cumulative count,state,hour from (select distinct
time,count(distinct num_id) as t_count,state,hour from (select * from
public.table1 where day=1 and time>0 order by time)as A group by
time,hour,state order by hour,state )B where state=1 and hour=1;
which gives me a results in the below format:
time t_count cumulative_t_count state hour
_____ _____ _________________ ____ ____
1 10 10 1 1
2 20 30 1 1
3 30 60 1 1
4 60 120 1 1
Likewise I have 80 state and hour from 0-23.I want to export all the results to CSV files by changing the state from 1-80 and for the hours 1,7,14,19.So now I am manually changing the state and hour in the above code and exporting the results as CSV.But it seems I have to change state 1 to 80 and hours 1,7,14,19 for each state.
BEGIN
FOR i IN 1..80 LOOP
FOR i IN 1,7,14,19 LOOP
/copy ( select time,t_count,sum(t_count) over (order by time) as
cumulative_t_count ,cumulative_t_count/sum(t_count) as percentage_cumulative count,state,hour from (select distinct
time,count(distinct num_id) as t_count,state,hour from (select * from
public.table1 where day=1 and time>0 order by time)as A group by
time,hour,state order by hour,state )B where state=i and hour=j)
To '/tmp/state_i_hour_j.csv' With CSV
END LOOP
END LOOP
But this did not work.I also want to export each result set in CSV format.Any help is appreciated.