Java java.time.format.DateTimeParseException on String

Question

I am trying to parse a date to convert it to epochs. I tried the solution of a similar question here without success:

String date = "Jun 4 2015";    
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("LLL dd yyyy").withLocale(Locale.ENGLISH);
LocalDateTime ldt  = LocalDateTime.parse(date, formatter);
System.out.println(date+" "+ldt.toEpochSecond(ZoneOffset.UTC));

And I get Exception in thread "main" java.time.format.DateTimeParseException: Text 'Jun 4 2015' could not be parsed at index 0 even though I am fairly certain that my regular expression is correct. What am I missing here?

EDIT:

Following the comments, I changed LocalDateTime to LocalDate, but keep getting the same error:

String date = "Jun 4 2015";    
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("MMM d yyyy").withLocale(Locale.ENGLISH);
LocalDate ldt  = LocalDate.parse(date, formatter);

http://stackoverflow.com/questions/30518954/datetimeformatter-month-pattern-letter-l-fails — Reimeus, Jul 01 '16 at 23:03
Using MMM is not sufficient. What you have there is a LocalDate, not a LocalDateTime: there is no time at all. Parse it to a LocalDate, then choose the time you want to transform it to a LocalDateTime. — JB Nizet, Jul 01 '16 at 23:06
I changed LocalDateTime to LocalDate and get the same issue... — Béatrice Moissinac, Jul 01 '16 at 23:10

score 7 · Accepted Answer · answered Jul 01 '16 at 23:11

    String date = "Jun 4 2015";
    DateTimeFormatter formatter = DateTimeFormatter.ofPattern("MMM d yyyy").withLocale(Locale.ENGLISH);
    LocalDate ldt  = LocalDate.parse(date, formatter);

parses fine. Don't put the "dd" as it won't parse days less than 10. As @JB Nizet said, you'll need to use LocalDate, not LocalDateTime.

Java java.time.format.DateTimeParseException on String

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