warning: missing terminating " character [enabled by default]

Question

I am getting this weird error below

json.c:81:19: warning: missing terminating " character [enabled by  default]
json.c:81:3: error: missing terminating " character
json.c:82:32: error: expected ‘,’ or ‘;’ before ‘:’ token
json.c:90:22: warning: missing terminating " character [enabled by default]
json.c:90:21: error: missing terminating " character

CODE:

int main()
{
  char * string = "{
                  "sender" : "joys of programming",

                   "receiver": [ "123",
                                 "345",
                                 "654",
                                 "432"
                               ]

                }";
 printf("JSON string: %sn", string);
 json_object * jobj = json_tokener_parse(string);
 json_parse(jobj);
 return 0;
 }

I understood error is about char * string line. But don't know how to fix it.

I tried escaping inner double quotes by adding "\" infront of each ,I am getting this error `error: stray "\" in program` — Naroju, May 23 '16 at 14:38
each of the parts of the string should be ended with something similar to "\n" \ Notice the trailing back slash. To make it easy for you, suggest writing a table of pointers to char strings, Then using a vary long string buffer, pass each line of the json commands into that buffer using one call to `strcpy()` and and several calls to `strcat()` be sure to include all the necessary escaped double quotes and include `\n` where ever a newline is needed, including at the end of the accumulated string. — user3629249, May 24 '16 at 06:54

LPs · Accepted Answer · 2016-05-23T14:48:55.017

2

You have to:

to escape " char because of it is a special char used to define a C-String literal.
For multi line strings you must define each line as a single C-String using "" for each one

So, the resulting code is

  char * string = "{"
                  "\"sender\" : \"joys of programming\","
                  "\"receiver\": [ \"123\","
                                  "\"345\","
                                  "\"654\","
                                  "\"432\""
                                "]"
                 "}";

edited May 23 '16 at 14:48

answered May 23 '16 at 14:39

LPs

16,045
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this answer is missing the newline characters between each line of the json command – user3629249 May 24 '16 at 06:56
@user3629249 I proposed a solution for the OP problem. I didn't tried to use the command using json. – LPs May 24 '16 at 07:00

Mirakurun · Answer 2 · 2016-05-23T14:43:09.600

1

You need to use escape character when using quotations marks inside quotation marks.

  char * string = "{ "
                  "\"sender\" : \"joys of programming\"," 

                   "\"receiver\": [ \"123\","
                                   "\"345\","
                                   "\"654\","
                                   "\"432\""
                               "]"

                "}";

This is going to do it.

edited May 23 '16 at 14:43

answered May 23 '16 at 14:35

Mirakurun

4,859
5
16
32

I tried escaping inner double quotes by adding "\" infront of each ,I am getting this error `error: stray "\" in program` – Naroju May 23 '16 at 14:39
This is what I get as an output when I print it out: { "sender" : "joys of programming","receiver": [ "123","345","654","432"]} – Mirakurun May 23 '16 at 14:44

warning: missing terminating " character [enabled by default]

2 Answers2