How MKI$ and CVI Functions works

Question

I am working on GwBasic and want to know how 'CVI("aa")' returns '24929' is that converts each char to ASCII but code of "aa" is 9797.

Why don't you see what `CVI("a")` returns? – Evan Trimboli May 17 '16 at 03:34 — Evan Trimboli, May 17 '16 at 03:34

score 3 · Accepted Answer · answered May 31 '16 at 12:18

CVI converts between a GW-BASIC integer and its internal representation in bytes. That internal representation is a 16-bit little-endian signed integer, so that the value you find is the same as ASC("a") + 256*ASC("a"), which is 97 + 256*97, which is 24929.

MKI$ is the opposite operation of CVI, so that MKI$(24929) returns the string "aa".

The 'byte reversal' is a consequence of the little endianness of GW-BASIC's internal representation of integers: the leftmost byte of the representation is the least significant byte, whereas in hexadecimal notation you would write the most significant byte on the left.

How MKI$ and CVI Functions works

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